![]() 10/07/2018 at 13:30 • Filed to: I wanna see if this supercharger would work | ![]() | ![]() |
How much airflow (in cubic feet/minute) would a 2.2l NA engine experience at WOT, and 6000 rpm? Need to know for reasons .
![]() 10/07/2018 at 13:35 |
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Assuming a four stroke and 100% volumetric efficiency (it can be higher!), it is drawing 2.2L*3000/minute, so 6600L/min. This works out to 233CFM average. There will be pulses higher and lower as the valves open and close.
![]() 10/07/2018 at 13:36 |
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It’s fairly simple math...
Assuming the engine is a 4-stroke and has 100% volumetric efficiency, it takes in 1.1 liters (half of the displacement - a 2-stroke takes in its full displacement) of air per revolution at WOT.
1.1 l/rev * 6000 rev/min = 6600 l/min.
At this point I resort to the Google to convert 6600 l to ft³, and get a result of 233.077 ft³/min.
![]() 10/07/2018 at 14:08 |
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Thank you! I think it works then; just wasn’t sure if the s/c I was looking at was big enough. Can confirm now it definitely is.
The engine in question has about 59% volumetric efficiency in its current state of tune...
![]() 10/07/2018 at 14:11 |
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Awesome. Thanks for the math, makes much more sense now. Can confirm the supercharger would be big enough for this application :)