![]() 11/10/2015 at 18:56 • Filed to: None | ![]() | ![]() |
need help with a homework question (its simple...but my brain is fried and its due tonight....)
Question: A 10mF capacitor is charged to 210 volts before the voltage supply becomes disconnected (eg. The instrument’s power was turned off). The capacitor discharges through a 10 mega-ohm resistance. How long does it take for the capacitor to reach the ‘safe’ voltage of 24V?
drifting Tesla for your time
was looking at one formula wrong. oops
![]() 11/10/2015 at 19:04 |
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2.6 millipumpernickels squared
![]() 11/10/2015 at 19:07 |
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http://www.daycounter.com/Calculators/Ca…
![]() 11/10/2015 at 19:15 |
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I thought it was 1.21 gigawatts.
![]() 11/10/2015 at 19:17 |
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The question is how long you silly goose, it needs to be a measure of time.
![]() 11/10/2015 at 19:22 |
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The calculator below should give you the right answer but I assume you would like to know how it works.
Warning math ahead (disclaimer: I am a AP Physics Teacher)
Not my powerpoint but similar to the one I use, in other news Kinja and Drive don’t play nice so I grabbed one from google.
Calculus explanation for charging and discharging
If you don’t care about calculus, I don’t this is why I’m not an EE.
This website will give you an algebraic answer
![]() 11/10/2015 at 19:22 |
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Oh well then, a waffel! Because motorcycles don’t need windshield wipers.
![]() 11/10/2015 at 19:23 |
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where F=farad, A= ampere , V= volt , C= coulomb , J= joule , m= metre , N= newton , s= second , W= watt , kg= kilogram , = ohm , H= henry .
One of these or a combination should do the trick.
![]() 11/10/2015 at 19:26 |
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...that looks mildly concerning. but I got figured out
![]() 11/10/2015 at 19:28 |
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But only if the Cup-Noodles are chicken flavoured
![]() 11/10/2015 at 19:32 |
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Argon walks into a bar, the bartender says we don’t serve noble gasses here. Argon doesn’t react.
![]() 11/10/2015 at 19:33 |
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Then we are in agreement.
![]() 11/10/2015 at 19:46 |
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or,
××ln10