Is this correct?

"Alex B" (alexb420)
05/22/2014 at 12:12 • Filed to: None

First you have to factor x^2-10x+25 and I got (x-5)(x-5). Next to subtract you have to get a common denominator (my teacher says that once you get a common denominator, you can basically "get rid" of the denominator.). Then you have to make everything equivalent, so I did. Then you combine like terms, and I got -18-4x.

DISCUSSION (10)

RamblinRover Luxury-Yacht > Alex B
05/22/2014 at 12:13

Nope. Should be +20, not -20. -4x*-5 = 20, not -20.

Rainbow > Alex B
05/22/2014 at 12:15

I think it's 22-4x. The -20 is being subtracted, so it becomes positive 20.

Lumpy44, Proprietor Of Fine Gif > RamblinRover Luxury-Yacht
05/22/2014 at 12:15

This.

RamblinRover Luxury-Yacht > Alex B
05/22/2014 at 12:16

Also, because it's not written as equal to anything, actually dividing out (x-5)(x-5) should not be done. Should be (22-4x)/(x-5)^2.

ttyymmnn > Alex B
05/22/2014 at 12:19

Sorry, I don't math. I gave it up after college and have been happy ever since.

Rainbow > RamblinRover Luxury-Yacht
05/22/2014 at 12:20

I think he's solving for X, but you're definitely right as far as we can see.

Vince-The Roadside Mechanic > Alex B
05/22/2014 at 12:20

I suck at math and am in it right now sooooooooooooooo I am no help, but have a great day.

KusabiSensei - Captain of the Toronto Maple Leafs > RamblinRover Luxury-Yacht
05/22/2014 at 12:20

I would expand it as 2 - (4x - 20). Now it's obvious as you distribute the negative one that you end up with 22 - 4x.

If I wanted to be extremely pedantic, the expression is actually (22 - 4x) / ((x-5)^2)

KusabiSensei - Captain of the Toronto Maple Leafs > Alex B
05/22/2014 at 12:22

Combining expression terms...joy.

Except you forgot to distribute the negative 1.

Correct answer is (22 - 4x) / ((x-5)^2)

KusabiSensei - Captain of the Toronto Maple Leafs > Rainbow
05/22/2014 at 12:35

You can't solve for X unless you have a value to compare it against. This is just an expression, which can be simplified, but not solved.